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Phrases Quadratic Equations PYQ



If the equation |x26x+8|=a has four real solution then find the value of a?





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Between any two real roots of the equation exsinx=1, the equation excosx=1 has





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Number of Roots

Given:

exsinx=1 has two real roots → say x1 and x2

Apply Rolle’s Theorem:

Since f(x)=exsinx is continuous and differentiable, and f(x1)=f(x2), ⇒ There exists c(x1,x2) such that f(c)=0

Compute:

f(x)=ex(sinx+cosx)=0tanx=1 At this point, excosx=1

At least one root



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Let C denote the set of all tuples (x,y) which satisfy x22y=0 where x and y are natural numbers. What is the cardinality of C?





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If α,β are the roots of x2x1=0 and An=αn+βn, the Arithmetic mean of An1 and An is





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If the roots of the quadratic equation x2+px+q=0 are tan 30° and tan 15° respectively, then the value of 2 + p - q is





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The quadratic equation whose roots are  is





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For what value of p, the polynomial  x43x3+2px26 is exactly divisible by (x1)





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α, β are the roots of the an equation x^2- 2x cosθ + 1 = 0, then the equation having roots αn and βn is





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The equation (x-a)3+(x-b)3+(x-c)3 = 0 has





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Let f(x) = (x – a)3 + (x – b)3 + (x – c)3.
Then f'(x) = 3{(x – a)2 + (x – b)2 + (x –c)2}
clearly , f'(x) > 0 for all x.
so, f'(x) = 0 has no real roots.
Hence, f(x) = 0 has two imaginary and one real root


Let  and  be the roots f the equation  and  are the roots of the equation , then the value of r,





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If α≠β and \alpha^2=5\alpha-3,\beta^2=5\beta-3, then the equation whose roots are \frac{\alpha}{\beta} and \frac{\beta}{\alpha} is 





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If \alpha and \beta are the roots of the equation 2x^{2}+ 2px + p^{2} = 0, where p is a non-zero real number, and \alpha^{4} and \beta^{4} are the roots of x^{2} - rx + s = 0, then the roots of 2x^{2} - 4p^{2}x + 4p^{4} - 2r = 0 are:





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If x and y are positive real numbers satisfying the system of equations x^{2}+y\sqrt{xy}=336 and y^{2}+x\sqrt{xy}=112, then x + y is:





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The value of k for which the equation (k-2)x^{2}+8x+k+4=0 has both real, distinct and negative roots is





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Roots of equation are ax^2-2bx+c=0 are n and m , then the value of \frac{b}{an^2+c}+\frac{b}{am^2+c} is





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If a + b + c = 0, then the value of 





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a, b, c are positive integers such that a^{2}+2b^{2}-2bc=100 and 2ab-c^{2}=100. Then the value of \frac{a+b}{c} is





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If x^{2} + 2ax + 10 - 3a > 0 for all x ∈ R, then





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